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Post by Ahatmose on Dec 4, 2012 23:42:20 GMT -5
Since we will comparing the planets to what is to be found at Giza I think it is important that we have the data at our fingertips. Here are the semi major axis' , the diameters and the orbital periods (length of a year in Earth days) for the eight planets of our solar system and the dwarf planet Ceres. Mercury: 57,909,050 km (35,983,015 miles) Diameter: 4879.4 km, Year = 87.979 days Venus: 108,208,930 km (67,237,912 miles) Mean Diameter: 12103.6 km, Year = 224.70 days Earth: 149,598,261 km ( 92,956,050 miles) Equatorial Diameter: 12756.28 km, Year = 365.2456 days Mars: 227,939,100 km (141,634,790 miles), Equatorial diameter: 6792.4 km, Year = 686.98 days Ceres: 413,690,604 km (257,055,424 miles), Diameter = 974.6 km, Year = 4.60 yr 1679.67 days Jupiter: 778,547,200 km (483,766,802 miles), Equatorial diameter = 142,984 km. Year = 4,332.59 days 11.8618 year 10,475.8 Jupiter solar days Saturn: 1,433,449,370 km (890,704,144 miles), Equatorial diameter = 120,536 km, Year = 10,759.22 days 29.4571 year 24,491.07 Saturn solar days Uranus: 2,876,679,082 km (1,787,485,511 miles) Equatorial diameter = 51,118 km, Year = 30,799.095 days 84.323326 year 42,718 Uranus solar days Neptune: 4,503,443,661 km (2,798,310,157 miles), Equatorial diameter = 49,528 km, Year = 60,190.03 days 164.79 years 89,666 Neptune solar days The main thing to remember is that the actual unit measure is not important although it will be shown that the designers simply used what was already in the heavens but what was really important was the ratio. If we use the ratio then it is unimportant what unit was used for the ratio of G1 to G2 will always be 440 / 411.04 = 1.0704554. what this means is that no matter how many unit measure are in G2 there will be 1.0704554 times more of them in G1. As an example let's say a unit measure of the builders was 43.2673 cubits or what they called a "Giza" There would then be 9.5 Gizas in G2 (9.5 x 43.2673 = 411.04) It follows then that in G1 there would be 9.5 x 1.0704554 Gizas in G1 or 10.1693263 x 43.2673 or 440.00 of the Egyptian cubits. The ratios would always be the same they would never vary. No matter what measurement any civilization used the ratio would always be 1 to 1.0704554. This will become clearer as we discover more and more ratios encoded for us at Giza. The builders knew that no matter what measurement system was used in the future the ratios would never change. The ratios would always point to the heavens and the planets. It was a master plan to be sure.
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Post by Ahatmose on Dec 5, 2012 11:25:44 GMT -5
In the geometry of our solar system and at Giza there are two "planets" that seem to be the scale on which the Giza Plateau was built. These are Mercury, messenger of "The Gods" and the now mislabeled dwarf planet, Ceres. Knowing the semi major axis' of these two the ratios at Giza all fall into place within the stylized rectangle which is almost but not quite the square root of two by the square root of three. We will start at Mercury and Mars and the ratio between them. This ratio equals 57,909,050 km divided into 227,939,100 km and we get 3.9356387300. If we allow Mercury to be represented by the base of G1 (I will show why this is logical a little later) we get 440 x 3.9356387300 or 1731.6810 and seems to fit one of the possibilities of the north south distance at Giza from the north side of G1 to the south side of G3 and checks to the square root of the speed of light to 97.987 % (√299792458 / 10 = 1731.4516) A second obvious ratio is the ratio 1/2 base G1 to base of G2. This ratio is 411.04 / 220 and gives us 1.868363636
Ratio of Venus and Mercury is 108,208,930 / 57.909.050 = 1.868601367 to 1.0000000
Accuracy of this ratio is 99.987 %
Conclusion drawn: The north south distance at Giza represents the distance to Mars when the base of G1 of 440.00 cubits represents the semi major axis of Mercury. The important thing to note here is that it does not matter at all what the correct unit of measurement is or if we even need it, it is the ratio that is all important. These ratios are 1.868363636 for Venus and 3.9356387300 for Mars. The ratios never change. So I repeat it makes no never mind what the unit of measure is, it is only the ratio that is important and really is what is being shown to us.
More with Ceres later.
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Post by Ahatmose on Dec 6, 2012 14:13:19 GMT -5
Some neat new observations that basically re-write much of what has gone before ... : IMAGE BELOW IS COPYRIGHT TO THE ESTATE OF CLIVE ROSS !!!!!!!!!!!!!!!!!!!!Mars = 227,939,100 kilometers Mercury = 57,909,050 kilometers Ratio = 3.93615678378 1731.4516 / 3.93615678378 = 439.8838 Speed of light is 299,792,458 m/sec Square root of this is 17314.516 Divide by 10 = 1731.4516 cubits Allowing 20.625 inches per cubit we get 35711.1889 inches East side of Giza Rectangle is 35710.45 (see diagram below) Accuracy to speed of light is 35710.45 / 35711.1889 = 99.9979 % Larger image here: img27.imageshack.us/img27/3789/petriegizatotal002large.pngAnd forgotten in all of this is my observation a while ago that the diameter of The Earth is 12756.28 kilometers and if we divide by 9 (remember this is in fact a 9 by 11 grid) we get 12756.28 / 9 = 1417.3644 within 0.07 of a cubit of my 1417.43 or less than an inch and a half. Meanwhile I had never noticed this before. See below. And Petrie has center of G1 to center of G3 as 29102 inches and 1410.99 x 20.625 = 29101.66875 This appears to be possibly a correct solution. db
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Post by Ahatmose on Dec 6, 2012 14:14:03 GMT -5
More proof that everything has a purpose at Giza. Clarifying: 440.00 (base of G1) / 201.50 (base of G3) = 2.1836228287841191066997518610422 9069.4 / 4153.9 = 2.1833457714437035075471243891283 If we draw a right angled triangle with short side equal to semi major axis of Mercury and hypotenuse equal to semi major axis of Venus then the resulting large angle is equal to 57.64526281685605126135682421165 1/sine = 1.183780842683162773397085265617 1.183780842683162773397085265617 + 1 = 2.183780842683162773397085265617 But interesting as well is that we get a stylized √2 by √5 by √7 triangle defining the ratios and distances of Mercury and Venus. Most interesting this Giza and our solar system
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Post by Ahatmose on Dec 6, 2012 16:25:38 GMT -5
Observation:1/10th the square root of the speed of light is 1731.4515817660047983788339758548 The length of a solar day on Earth is: Earth's rotation period relative to the Sun—its mean solar day—is 86,400 seconds of mean solar time (86,400.0025 SI seconds).[132] As the Earth's solar day is now slightly longer than it was during the 19th century due to tidal acceleration, each day varies between 0 and 2 SI ms longer.[133][134] en.wikipedia.org/wiki/Earth%27s_rotationIf we multiply the two together we get 1731.4515817660047983788339758548 x 86,400.0025 = 149,597,421 An astronomical unit is equal to: An astronomical unit (abbreviated as AU, au, a.u., or ua) is a unit of length equal to exactly 149,597,870,700 metres (92,955,807.273 mi)[1] or approximately the mean Earth–Sun distance. en.wikipedia.org/wiki/Astronomical_unitQuestion:Could the two be linked in some way or is it just a nice neat little co-incidence ? To work out exact we would need a solar day of 86400.262228191632320335548513596 Given the known parameters of slowing or speeding at what point in time would this have been correct ?
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Post by Ahatmose on Dec 7, 2012 0:55:04 GMT -5
In this diagram ... Pi shows up in a most unusual and interesting way. 1735.7600 - 1417.4342 = 318.32575361 1/318.32575361 x 1000 = 3.1414361 3.1414361 / Pi = 0.99995 or 99.995% accurate. Nice And maybe even nicer we have this. Radius = 1417.4342 Diameter = 2834.684 Circumference = 2834.684 x Pi = 8906.0020 Radius = 1735.7600 Diameter = 3471.5200 Circumference = 3471.5200 x Pi = 10906.1017 Differences in circumferences is 10906.1017 - 8906.0020 = 2000.0997 Basically the exact distance of "The Chase Line" Extremely neat !
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Post by Ahatmose on Dec 7, 2012 9:57:28 GMT -5
Ceres Ceres is said to be 413,690,604 kilometers from The Sun at it's semi major axis point however there is another distance which is said to be it's Proper orbital element and this distance is said to be 2.7670962 AU or 2.7670962 x 149597570.7 and equaling 413,951,700 kilometers. If we note a Mars' day is 686.98 days while an Earth day is 365.26 ( ... Earth orbits the Sun at an average distance of about 150 million kilometers every 365.2564 mean solar days, or one sidereal year. ...) The ratio of these two is 686.98 / 365.2564 = 1.88081577763. If we take the semi major axis' of Ceres and Jupiter we get this: 778,547,200 / 413951700 = 1.88076822 This ratio checks for 1.88076822 / 1.88081577763 = 0.999975 or 99.9975% CONCLUSION:There appear to be certain ratios that occur in more than one place in the solar system and I guess our job is to try to find out why. I think we will find eventually that Ceres is as important as Mercury in determining the ratios and distances of the planets. Mercury for the inner six and Ceres for the outer gas giants.
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Post by Ahatmose on Dec 7, 2012 11:53:05 GMT -5
I have pondering for over a decade about what the correct measurements at Giza are and today an idea occurred to me. Maybe it is not the measurements that changes but perhaps it must be the divisor that changes. That is to say that the north-south distance is and always will be 35,711.48242 inches HOWEVER the key to the solution may lie in the fact that there were indeed different distances for THE CUBIT. For example: 35,711.48242 / 20.625169 = 1731.4516 or the square root of the speed of light divided by 10 35,711.48242 / 20.618034 = 1732.0508 (square root of 3 x 1000) 35,711.48242 / 20.612688 = 1732.50 35,711.482427 / 20.61983 = 1731.90 The logical next question you will probably ask me is on what are they basing the different cubits. To this I would have to respond, I do not have a clue ... YET ! It's a thought. The total difference between all of them is 0.012481 of a cubit or about ONE QUARTER OF ONE INCH !!!!!!!!!!!!! And then there is this thought concerning "The Cubit" I have shown how it is most likely a ratio of the inner planets but there is another place we can find it. The diameter of The Sun is said to be 1,392,000 kilometers wide and so I decided to see if any ratios were to be found using this distance. I thought I would start at Saturn as it seems to be the cut off point for the ratios working properly and it could be suggested that Set (Saturn ?) and Horus (The Sun ?) could be likened to the battle for control of the solar system between The Sun and Saturn. But that is for another post let's see the ratio. The distance to Saturn from The Sun is 1,433,449,370 km so this divided by 1,392,000 equals 1029.7768 but really exactly how wide is The Sun ? Suppose, just suppose we called it 1,390,481.1397 what would this give us ? Well it would give us 1030.9017 ... well ... get to the point Don. In a minute let's try 1,390,000 even what would this give us ? This would give us 1031.2585 .. okay now the punchline Don. Well in the example that yields 1030.9017 if we multiply by 2 we get 2061.8034 and isn't that just 100 times the number of inches I say is in a cubit ? How about the second one. This we have 1031.2585 x 2 = 2062.52 or 100 times what we have concluded may be the number of inches in a cubit that yields 1/10th the square root of the speed of light. CONCLUSION: We have shown that the planets follow the ratio for the meter and the inch and the cubit and now we have shown that the diameter of The Sun and the sixth planet from The Sun, Saturn yields the same result only 50 times as large. Now how about that ? Over at the science board I suggested that the length of an Earth day in seconds was directly related to the square root of the speed of light and now I have another suggestion to make. If we use 86400 seconds but multiply by 10 we get 864000 and if we assume these are miles and multiply by the EXACT conversion factor of 1.609344 we get for the diameter of The Sun as 1390473.216 If we divide the semi major axis of Saturn of 1,433,449,370 by our new diameter of The Sun we get 1030.907574 and times 2 we get 2061.8151 Degree of accuracy to 20 + Phi of 20.618151 / 20.618034 = 99.99943 Nice and the precise same degree of accuracy as my other observation of seconds in an Earth day times 1/10 the square root of the speed of light equals an astronomical unit. Very nice I think. If we take 1,433,449,370 or semi major axis of Jupiter and divide by 2061.8034 (inches in a cubit x 100) we get 695240.5695. If we divide by 2 we get 347620 which is the diameter of The Moon x 100 (347628) to a degree of accuracy of 99.9977 % So if divide by two we get the diameter of The Moon (x 100) and if we multiply by 2 we get the diameter of The Sun. Now how neat is that !
db
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Post by Ahatmose on Dec 7, 2012 14:30:16 GMT -5
Diameter of Jupiter = 142,984 km Distance of Mars' semi major axis is 227,939,100 227,939,100 / 142,984 = 1594.1581 To see the significance we must return to this diagram: We just need to add one line --- db
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Post by Ahatmose on Dec 7, 2012 15:49:23 GMT -5
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Post by Ahatmose on Dec 7, 2012 22:58:36 GMT -5
It has been determined that 31/12 or 2.583333 is the correct value for the ratio of Mercury to Earth (57,909,100 x 2.58333 = 149598315) however Giza shows us yet another ratio if we use 280 (height of G1) as the distance to Mercury. Then 280 x 2.5833333 = 723.333333. If we divide by 1000 then we get .72333333 which is PRECISELY THE RATIO OF VENUS TO THE EARTH. 149597570.7 X .7233333 = 108,208,909.039 Distance to Venus = 108,208,930 108,208,909.039 / 108,208,930 = 0.9999998063 or 99.999981% accurate. Mars 227,939,100 / Mercury 57,909,100 = 3.936156783784 3.936156783784 x 280 = 1102.1239 So when height of G1 or 280 cubits = Mercury then Mars is the distance from the north side of G1 to the south side of G2 Very interesting ... not sure how I missed these before. 31/12 = 2.583333333333333333 This exactly defines the ratio of Mercury to Earth and also defines Earth to Venus when we use 280 but there is more. When we use the √2 / 2 and x 1000 we get 707.1067811865475 If we use our fraction of 31/12 we get 2.583333333 x 707.1067811865475 = 1826.6925. If assume this is a circumference we get as a diameter 581.45428752. If we further assume that this is a diagonal of a square we get as the sides of that square ... 411.15 and the largest side of G2 is 411.14. Very nice. Slope of G1 = √(220² + 280²) √(48400 + 78400) √126800 = 356.0898763 356.0898763 as a radius yields 356.0898763 x 2 x Pi = 2237.3787 √3/2 x 1000 = 866.02540378 x 2.5833333333 = 2237.2323 And now this: If we use 280 as a radius we get as a circumference 280 x 2 x Pi = 1759.291886 and as a square we get (divide by 4) 439.823 If we use slope of G1 we get 356.0898763 as a radius yields 356.0898763 x 2 x Pi = 2237.3787 or the diagonal of our rectangle If we use what is in the diagram of 2237.6426 as a slope we get 280 / 356.0898763 = 0.786318338812 x 2237.6426 = 1759.4994 and divide by 4 and we get 439.8748 An interesting geometrical jungle this Giza Plateau ...
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Post by Ahatmose on Dec 10, 2012 10:54:05 GMT -5
A possible celestial blueprint
√7 / √2 = 1.8708287 = Mercury to Venus (semi major axis)
√7 / √3 = 1.5275252 = Earth to Mars (semi major axis)
√7 / √4 = 1.3228757
√7 / √5 = 1.1832160 + 1 = 439.83 (G1) / 201.50 (G3)
√7 / √6 = 1.0801235
√7 / √7 = 1.0000000
Pi / √2 = 2.2214414691 and Pi x √2 = 4.4428829382
Pi / √3 = 1.8137993642 and Pi x √3 = 5.4413980927
Pi / √4 = 1.5707963268 and Pi x √4 = 6.2831853072
Pi / √5 = 1.40496294621 and Pi x √5 = 7.024814731041
Pi / √6 = 1.28254983016 and Pi x √6 = 7.695298980971
Pi / √7 = 1.187410411724 and Pi x √7 = 8.3118728820661
√Pi = 1.77245385090552 and Pi x √Pi = 5.5683279968317
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Post by Ahatmose on Dec 13, 2012 0:18:51 GMT -5
Today I had to wait 5 hours while my daughter finished her last exam and so I took Clive's book along with me. He was a firm believer in Pluto being found at Giza and while I have decided Pluto is not a planet some very unusual properties showed themselves when I began to study this planet. The major thing I noticed that if we take Pi of 3.1415926535897932384626433832795 and multiply by 2 we get 6.28318530718. If we then square this we get 39.478417604 Now that immediately looked familiar to me so I multiplied 39.478417604 by the semi major axis of Earth of 149,597,570.7 and got 5,905,875,369. I knew it was close but I did not know how close until I went to this website: simple.wikipedia.org/wiki/Pluto and found that the semi major axis of Pluto was 5,906,376,272 km or 39.48168677 AU and checking to a degree of accuracy of 99.992%. However I also cubed 2Pi and got 248.0502. This also immediately looked familiar and sure enough the length of the orbital period of Pluto is 90,613.305 days or 248.09 years. Degree of accuracy of this is 99.984 % Most unusual and interesting. Regards Don
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Post by Ahatmose on Dec 13, 2012 20:56:14 GMT -5
In anticipation of DUNE's thoughts and distances on G2 over at Graham's site I thought I would weigh in here with what I have found over the last couple of days. In very early posts of mine I noted that the south base of G2 was PRECISELY 4/11ths of the way towards the north from the south side of our Giza Rectangle. And I found it strangely eerie that no one commented on the beautiful FACT that the Ancient Builders proved this was intentional when they deliberately made the base of G2 411 cubits. I mean what an in your face thing to do. A pyramid which is 4/11ths of the way north is precisely 411 cubits. I mean really ... a co-incidence ? Hardly. But then I pointed out that the diagonal of this pyramid of 411.04 cubits yields 581.2983 cubits and if we allow this to equal a diameter we get as a circumference 1826.2026 cubits. I have also claimed that G2 is representing Venus and what could be more in your face than the circumference of 1826.2026 when divided by 5, the points of a pentagram, and doesn't Venus scribe a pentagram in the night skies every 8 years, giving us when divided 365.24 days and equaling an Earth year in solar days. However just recently I found another unusual property of 4/11ths that some may know but I did not. If we use the 4/11th line and form a triangle using the original diagonal we get the strange circumstance where the hypotenuse added to the short side is EXACTLY EQUAL TO our original starting line of 11.00 units. Here is the diagram. As you can see 7.727272727272 + 3.2727272727 (being 9/11ths of 4.000) = 11.0000 while 5.72727272727272 + 3.272727272727 = 9.0000. Here is another diagram. Please note that this is the only instance where it works. img824.imageshack.us/img824/4012/gizavenus1.png[/imgRegards Don Barone
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